n when n ≥ 4
since it uses induction and I am out of practise.Base case
For n = 4factorial(4) = 4*3*2*1 = 24
and 24 = 2*2*2*2 = 16
and 24 ≥ 16
so n when n = 4
Induction step
For n >= 4 assume we haven
and consider
≥ 2n × (n+1)
≥ 2n × 2 since (n+1) ≥ 2 when n ≥ 4
= 2n+1
(I also wanted to learn about writing maths in html)